49 lines
1.5 KiB
Python
49 lines
1.5 KiB
Python
#!/usr/bin/env python3
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# This is a component of LinuxCNC
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# Copyright 2011 Michael Haberler <git@mah.priv.at>
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#
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA.
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#
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#http://stackoverflow.com/questions/361/generate-list-of-all-possible-permutations-of-a-string
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def nextPermutation(perm):
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k0 = None
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for i in range(len(perm)-1):
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if perm[i]<perm[i+1]:
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k0=i
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if k0 == None:
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return None
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l0 = k0+1
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for i in range(k0+1, len(perm)):
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if perm[k0] < perm[i]:
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l0 = i
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perm[k0], perm[l0] = perm[l0], perm[k0]
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perm[k0+1:] = reversed(perm[k0+1:])
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return perm
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perm=["g88.1x1", "m405","m406","m407","m408"]
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while perm:
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print(perm)
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perm = nextPermutation(perm)
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perm=["g88.1x1", "m407","m408","m409","m410"]
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while perm:
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print(perm)
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perm = nextPermutation(perm)
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